2x^4+5x^2-12=0

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Solution for 2x^4+5x^2-12=0 equation:


Simplifying
2x4 + 5x2 + -12 = 0

Reorder the terms:
-12 + 5x2 + 2x4 = 0

Solving
-12 + 5x2 + 2x4 = 0

Solving for variable 'x'.

Factor a trinomial.
(-4 + -1x2)(3 + -2x2) = 0

Subproblem 1

Set the factor '(-4 + -1x2)' equal to zero and attempt to solve: Simplifying -4 + -1x2 = 0 Solving -4 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1x2 = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1x2 = 0 + 4 -1x2 = 0 + 4 Combine like terms: 0 + 4 = 4 -1x2 = 4 Divide each side by '-1'. x2 = -4 Simplifying x2 = -4 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(3 + -2x2)' equal to zero and attempt to solve: Simplifying 3 + -2x2 = 0 Solving 3 + -2x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2x2 = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2x2 = 0 + -3 -2x2 = 0 + -3 Combine like terms: 0 + -3 = -3 -2x2 = -3 Divide each side by '-2'. x2 = 1.5 Simplifying x2 = 1.5 Take the square root of each side: x = {-1.224744871, 1.224744871}

Solution

x = {-1.224744871, 1.224744871}

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